Twelve Days 2013: The Bellman-Ford Algorithm
Day Twelve: The Bellman-Ford Algorithm
TL/DR
If you need to find the shortest path for a graph with negative weights, the Bellman-Ford algorithm can do so. Dijkstra’s algorithm has better time complexity, but Bellman-Ford can handle graphs with negative weights, and even be used to detect negative cycles.
Detecting Negative Cycles
Today’s post is short and sweet—I might add code later but the algorithm is quite simple. For graphs with negative weights, Dijkstra’s algorithm fails. Negative weights introduce the potential for negative cycles, in which case a shortest path might not exist as a shorter path could always be constructed by transversing the cycle once again. That breaks Dijkstra. The Bellman-Ford algorithm can detect this when it happens. Unfortunately, the generality comes at the cost of time complexity. Dijkstra’s algorithm runs in . Bellman-Ford takes , where and are the sizes of the vertex and edge sets, respectively. There are modifications to Bellman-Ford with slightly better time complexity, but Bellman-Ford is quite simple to implement.
Finding Negative Cycles
Once you know that there is a negative cycle, you still need to find it. Depth-first search (DFS) is arguably the simplest route. You can run DFS on a subgraph that’s produced as a bi product running Bellman-Ford (the shortest path edge set that’s generated along the way) for slightly better time complexity. There’s a break even point between just running depth-first search on the full graph or starting off with Bellman-Ford to check if there’s a negative cycle in the first place. The run-time complexity of DFS is exponential for graphs with a branching factor greater than one so it’s not cheap. For really small graphs you’re almost certainly better off with a vectorized brute force search.
Why do we Care?
Finding a path via DFS, or the shortest path via Bellman-Ford, Dijkstra’s algorithm, or A-star has lots of applications in optimization and logistics. Here’s one nice example. Graphs with negative cycles are a special case of the shortest path problem, and once upon a time, currencies were inefficient enough that triangular arbitrage persisted for some time. These days, it’s a purely high frequency game.